A) 2.5 s and 7.5 s
B) 5.0 s and 7.5 s
C) 2.5 s and 5.0 s
D) 5.0 s and 10.0 s
Correct Answer: C
Solution :
| [c] \[~\phi (t)=\,AB\text{ }cos\text{ }\omega t\] |
| \[E=\frac{-\,d\phi }{dt}\,=AB\,\omega \,\sin \,\omega \,t=AB\,\omega \,\sin \,\left( \frac{2\pi }{T}\cdot t \right)\] |
| Induced emf, \[|\varepsilon |\]is maximum when |
| \[\frac{2\pi \,t}{T}=\frac{\pi }{2},\frac{3\pi }{2}\] |
| \[\Rightarrow \,\,t=\frac{T}{4}\] or \[\frac{3T}{4}\] i.e. 2.5 s or 7.5 s. |
| For induced emf to be minimum i.e zero |
| \[\frac{2\pi \,t}{T}=n\pi \Rightarrow \,t=n\frac{T}{2}\], |
| \[\Rightarrow \] Induced emf is zero at t = 5 s, 10 s |
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