JEE Main & Advanced
Physics
Atomic Physics
JEE PYQ-Atomic Physics
question_answer
Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be: [JEE Main 9-4-2019 Morning]