A) 5.5 ampere
B) 0.5 ampere
C) 0.004 ampere
D) 0.045 ampere
Correct Answer: D
Solution :
[d] |
\[{{r}_{A}}=\frac{l\times 120}{120+1}=\frac{120}{121}=1\,\,\Omega \] |
\[V=l(R+1)\] |
\[V=5.5(R+1)\] |
Without short resistance |
\[V=l'(R+120)\] ...(ii) |
Eq. (i) is equal to Eq. (ii) |
\[5.5(R+1)=l'(R+120)\] |
Hence, if the circuit has no resistance \[R=0\] |
\[5.5=l'(120)\]\[l'=\frac{5.5}{120}=0.045\,A\] |
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