| The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit? [AIEEE 2006] |
 |
A) 1.71 A
B) 2.00 A
C) 2.31 A
D) 1.33 A
Correct Answer: B
Solution :
| [b] We consider the diodes whether it is forward biased or reversed biased. Now, for a closed circuit (loop), KVL can be applied. |
| In the given circuit, diode\[{{D}_{1}}\]is reverse biased while\[{{D}_{2}}\]is forward biased, so the circuit can be redrawn as |
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| (\[\because \]for ideal, diodes, reverse biased means open circuited and forward biased means short circuited) |
| Apply KVL to get current flowing through the circuit |
| \[-12+4i-2i=0\] |
| \[\Rightarrow \] \[i=\frac{12}{6}=2A\] |
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