A)
B)
C)
D)
Correct Answer: A
Solution :
[a] \[{{V}_{d}}\propto \sqrt{E}\] \[I=neA{{V}_{d}}\] |
and \[E=\frac{V}{l}\]so \[E\propto V\]and \[I\propto {{V}_{d}}\] |
so \[I\propto \sqrt{V}\] \[{{I}^{2}}\propto V\] |
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