A) 2S = G
B) 2G = S
C) S(R+G) = RG
D) 2S(R+G) = RG
Correct Answer: C
Solution :
[c] Case-1 |
Case-2 |
\[{{i}_{1}}=\frac{{{V}_{E}}}{R+G}\] |
\[i=\frac{{{V}_{E}}}{R+\frac{GS}{G+S}}\] |
\[\frac{{{i}_{1}}}{2}G=\left( i-\frac{{{i}_{1}}}{2} \right)S\] |
\[{{i}_{1}}(G+S)=2iS\] |
substituting \[{{i}_{1}}\] and i we get S(R+G) = RG |
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