A) \[0.180\] g
B) \[0.141\] g
C) \[0.126\]g
D) \[0.242\] g
Correct Answer: C
Solution :
[c] According to Faraday's law of electrolysis, |
m = Zit, \[\frac{{{m}_{Zn}}}{{{m}_{Cu}}}=\frac{{{Z}_{Zn}}}{{{Z}_{Cu}}}\] |
\[\therefore \] \[\frac{0.13}{{{m}_{Cu}}}=\frac{32.5}{31.5}\] |
\[{{m}_{Cu}}=0.126\,\,g\] |
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