A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be [AIEEE 2003] |
A) 1 A
B) \[1.5\] A
C) 2 A
D) 1 A
Correct Answer: B
Solution :
[b] Resistance in the arms AC and 6C are in series, |
\[\therefore \] \[R'=3+3=6\,\Omega \] |
Now, R' and \[3\,\Omega \] are in parallel. |
\[\therefore \] \[{{R}_{eq}}=\frac{6\times 3}{6+3}=2\,\,\Omega \] |
Now, \[V=lR\] |
\[\Rightarrow \] \[l=\frac{3}{2}=1.5\,A\] |
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