A)
\[\frac{\text{mg}}{\text{3}\,\,\text{Ka}}\] B)
\[\frac{mg}{Ka}\]
C)
\[\frac{Ka}{mg}\]
D)
\[\frac{Ka}{3\,\,mg}\]
Correct Answer:
A Solution :
\[\therefore \frac{\Delta V}{V}=3\frac{dr}{r}\] So, \[K=\frac{mg/a}{3\frac{dr}{r}}\Rightarrow \frac{dr}{r}=\frac{mg}{3Ka}\]
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