A) 640
B)
641 C)
320
D)
321
Correct Answer:
B Solution :
\[0.320\,\times \,{{10}^{-3}}.\,\sin 30{}^\circ =n.500\,\,\times \,\,{{10}^{-9}}\] \[n\,\,=\,\,\frac{320\,\,\times \,{{10}^{-6}}}{500\,\times \,{{10}^{-9}}}\,\,\times \,\frac{1}{2}\,\,=\,\,\frac{16}{50}\,\times \,1000\,=\,320\] So, total no. of bright fringes \[=\text{ }2\left( 320 \right)+1=641\]
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