A) \[0.2\times {{10}^{6}}\text{ }N/{{m}^{2}}\]
B)
\[4.0\times {{10}^{6}}\text{ }N/{{m}^{2}}\] C)
\[1.8\times {{10}^{6}}\text{ }N/{{m}^{2}}\]
D)
\[1.2\times {{10}^{6}}\text{ }N/{{m}^{2}}\]
Correct Answer:
B Solution :
\[{{k}_{1}}=\frac{{{y}_{1}}{{A}_{1}}}{{{\ell }_{1}}}=\frac{120\times {{10}^{9}}\times A}{1}\] \[{{k}_{2}}=\frac{{{y}_{2}}{{A}_{2}}}{{{\ell }_{2}}}=\frac{60\times {{10}^{9}}\times A}{1}\] \[{{k}_{eq}}=\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}\times {{k}_{2}}}=\frac{120\times 60}{180}\times {{10}^{9}}\times A\] \[{{k}_{eq}}=40\times {{10}^{9}}\times A\] \[F={{k}_{eq}}(x)\] \[F=(40\times {{10}^{9}})A.(0.2\times {{10}^{-3}})\] \[\frac{F}{A}=8\times {{10}^{6}}N/{{m}^{2}}\] No option is matching. Hence question must be bonus.
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