A) \[-190V\]
B) \[-10V\]
C) \[10V\]
D) \[190V\]
Correct Answer: B
Solution :
| [b] Given that the variation of flux with time as |
| \[\phi =10{{t}^{2}}-50t+250\] |
| From Faraday's law of electromagnetic induction, |
| \[e=-\frac{d\phi }{dt}\] |
| \[=\frac{-d(10{{t}^{2}}-50t+250)}{dt}\] |
| \[\Rightarrow \]\[e=-[10\times 2t-50]\] |
| \[\therefore \]\[e{{|}_{t=3s}}=-[10\times 6-50]\] |
| \[=-10V\] |
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