A) 1
B) 2
C) \[1/2\]
D) 4
Correct Answer: A
Solution :
[a] Magnetic field in circular coil A is \[{{B}_{A}}=\frac{{{\mu }_{0}}\,Ni}{2\,R}\] where, R is radius and \[i\] is current flowing in coil. |
Similarly, \[{{B}_{B}}=\frac{{{\mu }_{0}}N(2i)}{2.\,(2R)}=\frac{{{\mu }_{0}}Ni}{2R}\] |
\[\Rightarrow \] \[\frac{{{B}_{A}}}{{{B}_{B}}}=\frac{1}{1}=1\] |
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