A) \[0.2\] H
B) \[0.4\] H
C) \[0.8\] H
D) \[0.1\] H
Correct Answer: D
Solution :
[d] The induced emf, \[e=-L\frac{di}{dt}=-L\frac{(-2-2)}{0.05}\] |
\[8=L\frac{(4)}{0.05}\] |
\[\therefore \] \[L=\frac{8\times 0.05}{4}0.1\,H\] |
You need to login to perform this action.
You will be redirected in
3 sec