A) \[\sqrt{2}\]
B) e
C) \[60{}^\circ \]
D) \[30{}^\circ \]
Correct Answer: D
Solution :
[d] The circuit is shown in figure below |
Rise of current in L-R circuit is given by |
\[l={{l}_{0}}\,(1-{{e}^{-t/\tau }})\] |
where\[{{l}_{0}}=\frac{E}{R}\,=\frac{R}{5}\,=1\,A\] |
Now, \[\left( -\frac{\pi }{2},\frac{\pi }{2} \right)\] |
After 2s, i.e., at \[\left[ -\frac{\pi }{2},\frac{\pi }{2} \right)\] |
Rise of current, |
\[l=(1-{{e}^{-1}})A\,\,\,\,(\because \,-t/\tau \,=\frac{-2}{2}=-1)\] |
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