A)
B)
C)
D)
Correct Answer: A
Solution :
[a] \[dB=\frac{{{\mu }_{0}}(dq)}{2r}\left( \frac{\omega }{2\pi } \right)\] |
\[B=\int{dB=\frac{{{\mu }_{0}}\omega }{4\pi }.\frac{Q}{\pi {{R}^{2}}}2\pi \int\limits_{0}^{R}{\frac{rdr}{r}}}\] |
\[B=\frac{{{\mu }_{0}}\omega Q}{2\pi {{R}^{2}}}.\,R\] |
\[B=\frac{{{\mu }_{0}}\omega Q}{2\pi R}\] |
\[B\propto \frac{1}{R}\] |
You need to login to perform this action.
You will be redirected in
3 sec