A) \[35.2\times {{10}^{-10}}J/{{m}^{3}}\]
B) \[35.2\times {{10}^{-11}}J/{{m}^{3}}\]
C) \[35.2\times {{10}^{-12}}J/{{m}^{3}}\]
D) \[35.2\times {{10}^{-13}}J/{{m}^{3}}\]
Correct Answer: C
Solution :
| [c] Given: Amplitude of electric field, |
| \[{{E}_{0}}=4v/m\] |
| Absolute permitivity, |
| \[{{\varepsilon }_{0}}=8.8\times {{10}^{-12}}{{c}^{2}}/N-{{m}^{2}}\] |
| Average energy density \[{{u}_{E}}=?\] |
| Applying formula, |
| Average energy density\[{{u}_{E}}=\frac{1}{4}{{\varepsilon }_{0}}{{E}^{2}}\] |
| \[\Rightarrow \]\[{{u}_{E}}=\frac{1}{4}\times 8.8\times {{10}^{-12}}\times {{(4)}^{2}}\] |
| \[=35.2\times {{10}^{-12}}J/{{m}^{3}}\] |
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