JEE Main & Advanced Physics EM Waves JEE PYQ-Electro Magnetic Waves

  • question_answer
    Consider an electromagnetic wave propagating in vacuum. Choose the correct statement:            [JEE ONLINE 10-04-2016]

    A) For an electromagnetic wave propagating in +y direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\hat{z}\]and the magnetic field is \[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{z}}\left( x,t \right)\hat{y}\]

    B)             For an electromagnetic wave propagating in +y direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\hat{y}\]and he magnetic field is \[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( x,t \right)\hat{z}\]

    C)             For an electromagnetic wave propagating in +x direction the electric field is             \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( y,z,t \right)\left( \hat{y}+\hat{z} \right)\] and the magnetic field is \[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( y,z,t \right)\left( \hat{y}+\hat{z} \right)\]

    D)             For an electromagnetic wave propagating in +x direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\left( \hat{y}-\hat{z} \right)\] and eh magnetic field is \[B=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( x,t \right)\left( \hat{y}+\hat{z} \right)\]

    Correct Answer: D

    Solution :

    [d] If wave is propagating in x direction, E must be functions of (x, t) & must be in y - z plane.


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