JEE Main & Advanced Physics EM Waves JEE PYQ-Electro Magnetic Waves

  • question_answer
    The magnetic field of a plane electromagnetic wave is given by :
    \[\vec{B}={{B}_{0}}\hat{i}[cos(kz-\omega t)]+{{B}_{1}}\hat{j}\cos (kz+\omega t)\] where \[{{B}_{0}}=3\times {{10}^{-5}}T\] and \[{{B}_{1}}=2\times {{10}^{-6}}T.\] The rms  value of the force experienced by a stationary charge \[Q={{10}^{-4}}C\]at \[z=0\]is closest to :         [JEE Main 9-4-2019 Morning]

    A)       \[0.9\text{ }N\]

    B) \[0.1\text{ }N\]

    C) \[3\times {{10}^{2}}N\]

    D) \[0.6N\]

    Correct Answer: D

    Solution :

    [d] Maximum Electric field E = [b] [c]
    Maximum force
                          (approx)
    Option [d]


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