question_answer

An electromagnetic wave is represented by the electric field \[\vec{E}={{E}_{0}}\hat{n}\sin [\omega t+(6y-8z)]\]. Taking unit vectors in x, y and z directions to be \[\hat{i}.\hat{j},\hat{k},\]the direction of propagation \[\hat{s},\] is: [JEE Main Held on 12-4-2019 Morning]

A) \[\hat{s}=\frac{4\hat{j}-3\hat{k}}{5}\]

B) \[\hat{s}=\frac{3\hat{j}-4\hat{j}}{5}\]

C) \[\hat{s}=\left( \frac{-3\hat{j}+4\hat{k}}{5} \right)\]

D) \[\hat{s}=\frac{-4\hat{j}+3\hat{j}}{5}\]

Correct Answer: C

Solution :

[c]

where and

direction of propagation