JEE Main & Advanced Physics EM Waves JEE PYQ-Electro Magnetic Waves

  • question_answer
    A plane electromagnetic wave is propagating along the direction \[\frac{\hat{i}+\hat{j}}{\sqrt{2}}\], with its polarization along the direction \[\hat{k}\]. The correct form of the magnetic field of the wave would be (here \[{{B}_{0}}\]is an appropriate constant) [JEE MAIN Held on 09-01-2020 Evening]

    A) \[{{B}_{0}}\frac{\hat{i}-\hat{j}}{\sqrt{2}}\cos \left( \omega t-k\frac{\hat{i}+\hat{j}}{\sqrt{2}} \right)\]

    B) \[{{B}_{0}}\hat{k}\cos \left( \omega t-k\frac{\hat{i}+\hat{j}}{\sqrt{2}} \right)\]

    C) \[{{B}_{0}}\frac{\hat{i}+\hat{j}}{\sqrt{2}}\cos \left( \omega t-k\frac{\hat{i}+\hat{j}}{\sqrt{2}} \right)\]

    D) \[{{B}_{0}}\frac{\hat{j}-\hat{i}}{\sqrt{2}}\cos \left( \omega t+k\frac{\hat{i}+\hat{j}}{\sqrt{2}} \right)\]

    Correct Answer: A

    Solution :

    [a] \[\vec{E}.\vec{B}=0\]
    \[\vec{E}\times \vec{B}\]is along \[\frac{\hat{i}+\hat{j}}{\sqrt{2}}\]


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