A) \[0.1\] V
B) 8V
C) 2 V
D) 3V
Correct Answer: A
Solution :
| [a] Potential difference between two points in an electric field is |
| \[{{V}_{A}}-{{V}_{B}}=\frac{W}{{{q}_{0}}}\] |
| where, W is work done by moving charge \[{{q}_{0}}\] from point A to B. |
| So. \[{{V}_{A}}-{{V}_{B}}=\frac{2}{20}\](here, \[W=2\,J,{{q}_{0}}=20C\]) |
| \[=0.1\,V\] |
You need to login to perform this action.
You will be redirected in
3 sec
