A) \[16\times {{10}^{-32}}\] J
B) \[3.1\times {{10}^{-26}}\] J
C) \[4\times {{10}^{-10}}\] J
D) \[32\times {{10}^{-32}}\] J
Correct Answer: D
Solution :
| [d] In this case, the work done is stored as electrostatic potential energy in the capacitor. |
| \[W=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\frac{{{q}^{2}}}{C}\] |
| \[=\frac{1}{2}\times \frac{{{(8\times {{10}^{-18}})}^{2}}}{100\times {{10}^{-6}}}\] |
| \[=\frac{1}{2}\times \frac{64\times {{10}^{-36}}}{100\times {{10}^{-6}}}=32\times {{10}^{-32}}J\] |
You need to login to perform this action.
You will be redirected in
3 sec
