A) 0
B) \[\frac{Q}{4\pi {{\varepsilon }_{0}}r_{1}^{2}}\]
C) \[\frac{Qr_{1}^{2}}{4\pi {{\varepsilon }_{0}}{{R}^{4}}}\]
D) \[\frac{Qr_{1}^{2}}{3\pi {{\varepsilon }_{0}}{{R}^{4}}}\]
Correct Answer: C
Solution :
[c] \[E=\frac{Q}{4\pi {{\varepsilon }_{0}}{{R}^{4}}}\int\limits_{r=0}^{{{r}_{1}}}{\frac{4\pi {{r}^{3}}dr}{\pi {{R}^{4}}}}\] \[=\frac{Q}{4\pi {{\varepsilon }_{0}}}\frac{r_{1}^{2}}{{{R}^{4}}}\].You need to login to perform this action.
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