A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{4{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{3{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{3}}}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{6{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{8{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]
Correct Answer: B
Solution :
[b] |
Both the charges of each dipole will interact with both the charges of to the dipole with an electrostatic force and then by vector sum, we can find the net force on the dipole. |
\[{{F}_{net}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\,\frac{3{{p}_{1}}{{p}_{2}}}{{{X}^{4}}}\] |
You need to login to perform this action.
You will be redirected in
3 sec