In figure is shown a system of four capacitors connected across a 10 V battery. |
Charge that will flow from switch S when it is closed is: [JEE MAIN 11-04-2015] |
A) \[5\mu C\] from b to a
B) \[20\mu C\] from a to b
C) \[5\mu C\] from a to b
D) zero
Correct Answer: A
Solution :
[a] |
for upper link \[{{C}_{eq}}=\frac{6}{5}\mu F\] |
\[\therefore \]\[{{\text{Q}}_{\text{upper}}}={{\text{Q}}_{\text{lower}}}=12\mu C\]on closing switch charge on \[2\mu F\]is \[10\mu C\And \]that on \[3\mu F\]is \[15\mu C\] |
\[\therefore \]\[{{q}_{i}}=-12+12=0\] |
\[\therefore \]\[{{q}_{j}}=15-10=5\mu C\] |
\[\therefore \] \[\] |
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