A) \[{{60}^{o}}\]
B) \[{{90}^{o}}\]
C) \[{{30}^{o}}\]
D) \[{{45}^{o}}\]
Correct Answer: A
Solution :
[a] So from\[\vec{\tau }=\vec{p}\times \vec{E}\] |
\[\tau \hat{k}-\tau \hat{k}=\left( {{p}_{x}}\hat{i}+{{p}_{y}}\hat{j} \right)\times \left( E\hat{i}+\sqrt{3}E\hat{j} \right)\] |
\[={{p}_{x}}\sqrt{3}E\hat{k}+{{p}_{y}}E\left( -\hat{k} \right)\] |
\[0=E\hat{k}\left( \sqrt{3}{{p}_{x}}-{{p}_{y}} \right)\] |
\[\frac{{{p}_{y}}}{{{p}_{x}}}=\sqrt{3}\] |
\[\therefore \] \[\tan \theta =\sqrt{3}\] |
\[\theta ={{60}^{o}}\] |
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