question_answer

A parallel plate capacitor has\[1\mu F\] capacitance. One of its two plates is given\[+2\mu C\]charge and the other plate, \[+4\mu C\] charge. The potential difference developed across the capacitor is:- [JEE Main 8-4-2019 Afternoon]

A) 5V

B) 2V

C) 3V

D) 1V

Correct Answer: D

Solution :

[d]

Charges at inner plates are \[1\mu C\]and \[1\mu C\]

\[\therefore \]Potential difference across capacitor

\[=\frac{q}{c}=\frac{1\mu C}{1\mu F}=\frac{1\times {{10}^{-6}}C}{1\times {{10}^{-6}}Farad}=1V\]