A) Only when the Gaussian surface is an equipotential surface and \[\left| {\vec{E}} \right|\] is constant on The surface.
B) Only when\[\left| {\vec{E}} \right|=\] constant on the surface.
C) Only when the Gaussian surface is a equipotential surface.
D) For any choice of Gaussian surface.
Correct Answer: A
Solution :
| [a] By Gauss law |
| \[\oint{\vec{E}\cdot \overrightarrow{dA}}=\frac{{{Q}_{in}}}{{{\varepsilon }_{0}}}\] |
| If \[\left| {\vec{E}} \right|=\frac{{{Q}_{in}}}{\left| {\vec{A}} \right|{{\varepsilon }_{0}}}\] |
| or \[\left| {\vec{E}} \right|\left| {\vec{A}} \right|=\frac{{{Q}_{in}}}{{{\varepsilon }_{0}}}\] |
| Then \[\vec{E}||\vec{A}\] |
| \[\therefore \] Surface is equipotential too. |
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