A) \[\cos \theta \]
B) \[\cot \theta \]
C) \[\sin \theta \]
D) \[\tan \theta \]
Correct Answer: D
Solution :
| [d] Electric field due to a charged conducting sheet of surface charge density \[\sigma \] is given by |
| \[E=\frac{\sigma }{{{\varepsilon }_{0}}\,{{\varepsilon }_{r}}}\,=\frac{l}{2{{\varepsilon }_{0}}}\] |
where, permittivity in vacuum and is relative permittivity of medium. |
| Let the charge on the ball B is Q, then electrostatic force on it |
 |
| FBD of B is shown in figure. |
 |
| In equilibrium, |
 ...(i) |
and  ...(ii) |
| Thus, on dividing Eq. (ii) by Eq. (i), we get |
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  or  |
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