A) \[{{y}^{2}}=x\]
B) \[y=|\text{ }x|\]
C) \[\frac{2}{3}\]
D) zero
Correct Answer: D
Solution :
| [d] On introduction and removal and again on introduction, the capacity and potential remain same. So, net work done by the system in this process |
| \[x=(2\times {{10}^{-2}})\cos \pi t\] |
You need to login to perform this action.
You will be redirected in
3 sec
