The equivalent capacitance between A and B in the circuit given below is: [JEE Online 15-04-2018] |
A) \[4.9\mu F\]
B) \[3.6\mu F\]
C) \[5.4\mu F\]
D) \[2.4\mu F\]
Correct Answer: D
Solution :
[d] \[{{C}_{1}}=5+5+2=12\mu F\] |
\[{{C}_{2}}=4+2=6\mu F\] |
\[1/{{C}_{Eq}}=1/6+1/12+1/6=5/12\] |
\[{{C}_{Eq}}=2.4\mu F\] |
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