A) +Q/2
B) -Q/4
C) +Q/4
D) -Q/2
Correct Answer: B
Solution :
[b] |
\[\frac{kQq}{{{\left( \frac{d}{2} \right)}^{2}}}\,\,=\,\,\frac{k{{Q}^{2}}}{{{d}^{2}}}\] |
\[q\,\,=\,\,\frac{Q}{4}\,\,\frac{{{d}^{2}}}{{{d}^{2}}}\] |
\[q\,\,=\,-\,\frac{Q}{4}\,\,\] |
Option (2) is correct. |
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