A) \[({{\phi }_{1}}-{{\phi }_{2}}){{\varepsilon }_{0}}\]
B) \[({{\phi }_{1}}+{{\phi }_{2}})/{{\varepsilon }_{0}}\]
C) \[({{\phi }_{1}}-{{\phi }_{2}})/{{\varepsilon }_{0}}\]
D) \[({{\phi }_{1}}+{{\phi }_{2}}){{\varepsilon }_{0}}\]
Correct Answer: A
Solution :
| [a] From Gauss's law, |
| \[\frac{Charge\text{ }enclosed}{{{\varepsilon }_{0}}}=\] Flux leaving the surface |
| \[\frac{q}{{{\varepsilon }_{0}}}={{\phi }_{2}}-{{\phi }_{1}}\] (i.e, net flux) |
| \[\Rightarrow \] \[q=({{\phi }_{2}}-{{\phi }_{1}}){{\varepsilon }_{0}}\] |
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