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JEE Main & Advanced Physics Electrostatics & Capacitance JEE PYQ-Electrostatics and Capacitance

  • question_answer
    A cone of base radius R and height h is located in a uniform electric field \[\overset{\to }{\mathop{E}}\,\] parallel to its base. The electric flux entering the cone is: [JEE ONLINE 11-04-2014]

    A) \[\frac{1}{2}EhR\]

    B) her

    C) 2 E h R

    D) 4 E h R

    Correct Answer: B

    Solution :

    [b] Electric flux, \[\phi =E(ds)cos\theta \]             \[=E(hR)\text{ }cos0{}^\circ =EhR\]


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