A) - 48 V
B) - 520 V
C) 180 V
D) 320 V
Correct Answer: C
Solution :
[c] \[\vec{E}=(20x+10)\hat{i}\] |
\[{{V}_{1}}-{{V}_{2}}-\int\limits_{-5}^{1}{(20x+10)dx}\] |
\[{{V}_{1}}-{{V}_{2}}=-(10{{x}^{2}}+10x)_{-5}^{1}\] |
\[{{V}_{1}}-{{V}_{2}}=10(25-5-1-1)\] |
\[{{V}_{1}}-{{V}_{2}}=180V\] |
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