A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by : |
[JEE Main 10-4-2019 Afternoon] |
A) \[2\pi \sqrt{\frac{L}{\sqrt{{{g}^{2}}+{{\left( \frac{qE}{m} \right)}^{2}}}}}\]
B) \[2\pi \sqrt{\frac{L}{\sqrt{g+\left( \frac{qE}{m} \right)}}}\]
C) \[2\pi \sqrt{\frac{L}{\left( g-\begin{matrix} qE \\ m \\ \end{matrix} \right)}}\]
D) \[2\pi \sqrt{\frac{L}{\left( {{g}^{2}}-\begin{matrix} {{q}^{2}}{{E}^{2}} \\ {{m}^{2}} \\ \end{matrix} \right)}}\]
Correct Answer: A
Solution :
[a] |
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