A) \[3\times {{10}^{4}}C/{{m}^{2}}\]
B) \[6\times {{10}^{4}}C/{{m}^{2}}\]
C) \[6\times {{10}^{-7}}C/{{m}^{2}}\]
D) \[3\times {{10}^{-7}}C/{{m}^{2}}\]
Correct Answer: C
Solution :
[c] |
\[K=2.2\] |
\[d=5mm\] \[E=3\times {{10}^{4}}\frac{v}{m}\] |
\[\frac{\sigma }{k{{\in }_{0}}}=3\times {{10}^{4}}\] |
\[\sigma =k{{\in }_{0}}\times 3\times {{10}^{4}}\] |
\[=2.2\times 8.85\times {{10}^{-12}}\times 3\times {{10}^{4}}\] |
\[=58.41\times {{10}^{-8}}=5.84\times {{10}^{-7}}=6\times {{10}^{-7}}c/{{m}^{2}}\](approx.) |
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