JEE Main & Advanced
Physics
Electrostatics & Capacitance
JEE PYQ-Electrostatics and Capacitance
question_answer
A cone of base radius R and height h is located in a uniform electric field \[\overset{\to }{\mathop{E}}\,\] parallel to its base. The electric flux entering the cone is: [JEE ONLINE 11-04-2014]
A)\[\frac{1}{2}EhR\]
B)her
C)2 E h R
D)4 E h R
Correct Answer:
B
Solution :
[b] Electric flux, \[\phi =E(ds)cos\theta \] \[=E(hR)\text{ }cos0{}^\circ =EhR\]