A capacitance of \[2\mu F\]is required in an electrical circuit across a potential difference of 1.0 kV. A large number of\[1\mu F\]capacitors are available which can withstand a potential difference of not more than 300 V. |
The minimum number of capacitors required to achieve this is: [JEE Main 2017] |
A) 24
B) 32
C) 2
D) 16
Correct Answer: B
Solution :
[b] To hold 1 KV potential difference minimum four capacitors are required in series |
\[\Rightarrow \]\[{{C}_{1}}=\frac{1}{4}\]for one series. |
So for Ceq to be \[2\mu F,8\]parallel combinations are required. |
\[\Rightarrow \] Minimum no. of capacitors \[=8\times 4=32\] |
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