A) 32 mm
B) 16 mm
C) 28 mm
D) 20 mm
Correct Answer: B
Solution :
| [b] Energy of sphere\[=\frac{{{Q}^{2}}}{2C}\] |
| \[4.5=\frac{16\times {{10}^{-12}}}{2C}\] |
| \[C=\frac{16\times {{10}^{-12}}}{9}=4\pi {{\varepsilon }_{0}}R\] |
| \[R=\frac{16\times {{10}^{-12}}}{9}\times \frac{1}{4\pi {{\varepsilon }_{0}}}\] |
| \[=9\times {{10}^{9}}\times \frac{16}{9}\times {{10}^{-12}}\] |
| \[=16\times {{10}^{-3}}=16mm\] |
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