| Four closed surfaces and corresponding charge distributions are shown below - |
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| Let the respective electric fluxes through the surfaces be \[{{\Phi }_{1}},\,{{\Phi }_{2}},\,{{\Phi }_{3}}\] and \[{{\Phi }_{4}}\]. Then - [JEE Online 09-04-2017] |
A) \[{{\Phi }_{1}}>{{\Phi }_{2}}>{{\Phi }_{3}}>{{\Phi }_{4}}\]
B) \[{{\Phi }_{1}}<{{\Phi }_{2}}={{\Phi }_{3}}>{{\Phi }_{4}}\]
C) \[{{\Phi }_{1}}>{{\Phi }_{3}};\,\,{{\Phi }_{2}}>{{\Phi }_{4}}\]
D) \[{{\Phi }_{1}}={{\Phi }_{2}}={{\Phi }_{3}}={{\Phi }_{4}}\]
Correct Answer: D
Solution :
[d] Eq = same in all \[\Phi =\] Same
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