A) 6 cm
B) 12 cm
C) 4.8 cm
D) 2.4 cm
Correct Answer: D
Solution :
[d] As we enter a soap bubble the pressure increases by \[\frac{4T}{R}\] |
Here is radius of bubble, and is surface tension. |
\[{{P}_{2}}={{P}_{0}}+\frac{4T}{4}+\frac{4T}{6}\] |
\[{{p}_{2}}={{P}_{0}}+\frac{5}{12}\times 4T\] |
\[{{p}_{2}}-{{P}_{0}}=\frac{4T}{\frac{12}{5}}\] |
So for a single bubble to have a pressure difference of\[{{P}_{2}}-{{P}_{0}}\] |
\[R=\frac{12}{5}=2.4\,cm\] |
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