A) 6.0 m
B) 9.6 m
C) 2.9 m
D) 4.8 m
Correct Answer: D
Solution :
[d] |
\[r\,\,=\,\,2\,cm\] |
\[a=\pi {{\left( 2\times {{10}^{-2}} \right)}^{2}}=\pi \,\,\times 4\times {{10}^{-}}^{4}{{m}^{2}}\] |
\[\because \,\,A>>a\] |
\[\Rightarrow \,\,\,V\,\,=\,\,\sqrt{2gh}\] |
Volume flow rate = \[Av=0.74{{m}^{3}}/min\] |
\[=\,\,\frac{0.74}{60}\,{{m}^{3}}/\sec \] |
\[4\pi \,\,\times \,\,{{10}^{-4}}\,v=\,\,\frac{0.74}{60}\,\] |
\[v\,\,=\,\,\frac{0.74}{4\pi \,\times \,{{10}^{-4}}\,\times \,\,60}\,\,=\,\frac{0.74\,\times {{10}^{4}}}{4\times 3.14\,\times 60}\] |
\[v\,\,=\,\,\frac{7400}{12.56\,\times \,60}\,\,=\,\,\sqrt{2gh}\] |
\[\,\,\frac{740}{75.36}\,\,=\,\,\sqrt{2gh}\] |
\[h\,\,\approx \,\,4.8\,m\] |
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