A)
B)
C)
D) None of these
Correct Answer: D
Solution :
| [d] \[\frac{dV}{dt}=\cos nt.\]or,\[\frac{d\left( \frac{4}{3}\pi {{r}^{3}} \right)}{dt}=K\] |
| \[\frac{4}{3}\pi (3{{r}^{2}})\frac{dr}{dt}=K,4\pi {{r}^{2}}\frac{dr}{dt}=K\] |
| \[\Rightarrow \]\[{{r}^{3}}=Kt+C\Rightarrow r={{K}_{1}}{{t}^{1/3}}+{{C}_{1}}\] |
| The excess pressure inside the bubble is\[\frac{4S}{r}\] |
| i.e. \[{{P}_{excess}}\propto \frac{1}{r}\]pressure, \[P={{P}_{0}}+\frac{4S}{r}\]\[={{P}_{0}}+\frac{4S}{{{K}_{1}}{{t}^{1/3}}+{{C}_{1}}}\] |
| * None of the given options is correct. |
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