A) \[{{10}^{8}}N/{{m}^{2}}\]
B) \[{{10}^{4}}N/{{m}^{2}}\]
C) \[{{10}^{3}}N/{{m}^{2}}\]
D) \[{{10}^{16}}N/{{m}^{2}}\]
Correct Answer: C
Solution :
[c] Note : |
Pressure is defined as normal force per unit area. |
Force is calculated as change in momentum/ time |
By this answer is \[2N/{{m}^{2}}\] |
None of the option matches so this question must be Bonus |
Detailed solution is as following. |
Magnitude of change in momentum per collision = 2mv |
Pressure \[=\frac{Force}{Area}=\frac{N(2mv)}{1}\] |
\[=\frac{{{10}^{22}}\times 2\times {{10}^{-26}}\times {{10}^{4}}}{1}\] |
\[=2N/{{m}^{2}}\] |
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