A) \[\frac{m{{\overline{\text{v}}}^{2}}}{6{{k}_{B}}}\]
B) \[\frac{m{{\overline{\text{v}}}^{2}}}{5{{k}_{B}}}\]
C) \[\frac{m{{\overline{\text{v}}}^{2}}}{3{{k}_{B}}}\]
D) \[\frac{m{{\overline{\text{v}}}^{2}}}{7{{k}_{B}}}\]
Correct Answer: C
Solution :
[c] According to equipartion energy theorem |
\[\frac{1}{2}m\left( \text{v}_{rms}^{2} \right)=3\times \frac{1}{2}{{K}_{b}}T\] |
\[T=\frac{m\overline{\text{v}}_{rms}^{2}}{3k}\] |
\[\therefore \]correct option should be [c] |
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