A) 11q
B) 5q
C) 3q
D) 2q
Correct Answer: A
Solution :
| [a] \[\vec{F}=q[\vec{E}+\vec{v}\times \vec{B}]\] |
| \[=q\left[ 3\hat{i}+\hat{j}+\hat{k}+3\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 3 & 4 & 1 \\ 1 & 1 & -3 \\ \end{matrix} \right| \right]\] |
| \[=q[3\hat{i}+\hat{j}+2\hat{k}+\hat{i})-12-1)-\hat{j}(-9-1)+\hat{k}(3-4)]\] |
| \[=q[3\hat{i}+\hat{j}+2\hat{k}-13\hat{i}10-\hat{j}-\hat{k}]\] |
| \[=q[-10\hat{i}+11\hat{j}+\hat{k}]\] |
| \[={{F}_{y}}=11q\,\hat{j}.\] |
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