A) \[\left( \frac{M{{v}^{2}}}{R} \right)2\pi R\]
B) zero
C) BQ \[2\pi R\]
D) BQv \[2\pi R\]
Correct Answer: B
Solution :
[b] When particle describes circular path in a magnetic field, its velocity is always perpendicular to the magnetic force. | ||||||||
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W = 0 (everywhere) |
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