JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव JEE PYQ-Magnetic Effects Of Current

  • question_answer
    A particle of mass M and charge Q moving with velocity v describes a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field when the particle completes one full circle is [AIEEE 2003]

    A) \[\left( \frac{M{{v}^{2}}}{R} \right)2\pi R\]

    B) zero

    C) BQ \[2\pi R\]

    D) BQv \[2\pi R\]

    Correct Answer: B

    Solution :

    [b] When particle describes circular path in a magnetic field, its velocity is always perpendicular to the magnetic force.
    Power  \[P=F.\,v=Fv\cos \theta \]
    Here,       \[\theta ={{90}^{o}}\]
    \[\therefore \] P = 0
    But,       \[P=\frac{W}{t}\Rightarrow W=P.\,\,t\]
    Hence, work done
    W = 0          (everywhere)


You need to login to perform this action.
You will be redirected in 3 sec spinner