A) \[2\sqrt{2}\]
B) \[27\]
C) \[36\]
D) \[8\]
Correct Answer: B
Solution :
[b] Magnetic at centre \[O=\frac{{{\mu }_{0}}ni}{2R}\] (i) |
Magnetic field at point, |
\[P=\frac{{{\mu }_{0}}ni{{R}^{2}}}{2{{[{{R}^{2}}+{{(2\sqrt{2}R)}^{2}}]}^{3/2}}}\] (ii) |
Dividing Eq. (i) by (ii), we get |
\[=\frac{{{\mu }_{0}}ni}{2R}\times \frac{2\,({{R}^{2}}+8{{R}^{2}})}{{{\mu }_{0}}ni{{R}^{2}}}=\frac{{{(9{{R}^{2}})}^{3/2}}}{{{R}^{3}}}\] |
\[={{(3)}^{3}}=27\] |
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